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An average computer mouse inspector can inspect 55 mice per hour with a population standard deviation of 14 mice per hour. The 44 computer mice inspectors at a particular factory can only inspect 50 mice per hour. Does the company have reason to believe that these inspections are slower than average at a=0.10?
a box contains 10 chips. the chips are numbered 1 through 10. otherwise the chips are identical. from this box we draw
a suppose that a newspaper in wisconsin wants to take a statewide survey concerning state budgetary issues. the
i just need someone to answer all the question with a paragraph each. just needs to be a page 1-2 pages max. i am a
for the following sample8 1 51 5a. find the mean and the standard deviation.b. now change the score of x8 to x18 and
According to a survey 41 % of major US companies electronically monitor their employees. Suppose that 5 such companies are selected independently and at random.
The probability of an randomly selected person quits a team is 0.125. Assume the team has n members. Determine the smallest n that the team needs to have if the probability of the team has at least 20 members left is 0.9.
Sample without replacement when testing batches of products. When sampling without replacement, should you use the multiplication rule for independent or dependent events.
Estimate the population in 1600 and graph the population trend from 1600 through to 2000
The Spanish patients, two men and two women, were elderly and very ill. All four had undergone routine dialysis at the Hospital de la Princesa. Soon after, they began sweating and vomiting, some of them in excruciating pain. They died within a few..
Suppose a reading between 30 and 40 is called very interesting from an archaeological point of view. Let us say you take readings at n=12 sites chosen at random.
The trend line y = 0.70 + 0.005t was calculated from quarterly data for 1999 -2003, where t = 1 for the first quarter of 1999. The seasonal indexes computed from the trend line for the four quarters of the year 2004 were .85, 1.05, 1.15, and .80, ..
For the following scores, find the (A) mean, (B) median, (C) sum of squared deviations, (D) variance, and (E) standard deviation:
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