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Aluminum reacts with chlorine gas to form aluminum chloride

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Reference no: EM131353654

Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction:  2Al(s)+3Cl2(g)→2AlCl3(s) You are given 24.0 g of aluminum and 29.0 g of chlorine gas.

1.  If you had excess chlorine, how many moles of aluminum chloride could be produced from 24.0 g of aluminum? 

2. If you had excess aluminum, how many moles of aluminum chloride could be produced from 29.0 g of chlorine gas, Cl2?

Reference no: EM131353654

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