Aluminum dissolves in an aqueous solution of naoh according

Aluminum dissolves in an aqueous solution of NaOH according to the following reaction:

2 NaOH + 2 Al + 2 H2O -----> 2 NaAlO2 + 3 H2

If 84.1 g of NaOH and 51.0 g of Al react:

i) Which is the limiting reagent?

ii) How much of the other reagent remains?

iii) What mass of hydrogen is produced?

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Aluminum dissolves in an aqueous solution of naoh according : aluminum dissolves in an aqueous solution of naoh according to the following reaction2 naoh 2 al 2 h2o -----gt 2

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