Adams and jones call on three and four customers

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Salespersons Adams and Jones call on three and four customers, respectively, on a given day. Adams could make 0, 1, 2, or 3 sales, whereas Jones could make 0, 1, 2, or 3 sales. The sample space listing the number of possible sales for person on a given day is given in the following table. Here (0, 1) stands for 0 sales by Adams and 1 sale by Jones. Assume that each sample point is equally likely.

Jones Adams 0------1------2------3

0 {0, 0} {1, 0} {2, 0} {3, 0}

1 {0, 1} {1, 1} {2, 1} {3, 1}

2 {0, 2} {1, 2} {2, 2} {3, 2}

3 {0, 3} {1, 3} {2, 3} {3, 3}

Let us define the events: 

A = each made the same number of sales 

B = Adams made exactly one sale 

1. List the sample space for Event A and event B. 

2. Find the total number of the sample space. S(n) = 

3. Find the following probabilities: 

(1) P(A) =

(2) P(B) =

(3) P(A∩B) =

(4) P(A∪B) =

(5) P(A|B) =

Reference no: EM132388414

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