A program that multiplies a number by shifting left

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Reference no: EM132207516

Question :

Write a Pep/9 assembler program that multiplies a number by shifting left. Each shift left doubles the number.

For example, if we shift 0x02 one bit to the left the answer is 0x04 (0000 0010 shifted left is 0000 0100). Multiply 0x28 by 0x10 (in decimal it is 40 times 16, but leave the answer in hex).

Reference no: EM132207516

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