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A journal article reports that a sample of size 5 was used as a basis for calculating a 95% CI for the true average natural frequency (Hz) of delaminated beams of a certain type. The resulting interval was (229.664, 233.404). You decide that a confidence level of 99% is more appropriate than the 95% level used. What are the limits of the 99% interval? [Hint: Use the center of the interval and its width to determine x and s.] (Round your answers to three decimal places.)
Suppose the correlation between two variables x and y is due, in part, to the fact that y is responding to changes in some unobserved third variable. What is this due to?
When creating a 99% confidence interval for the true average difference in cholesterol levels by the drug, what is the margin of error?
a doctor wants to estimate the hdl cholesterol of all 20-to 29- year-old females. how many sunjects are needed to
The counts in the five groups are 113, 95, 108, 99, and 85, respectively. The probabilities for these five intervals are all the same. What is this probability?
Is the GPA of this year's students significantly different from the long-run average? At what alpha level would it be significant?
what is the probablitiy of getting a exactly one head b exactly one tail and c not b in 4 coin
Marconi Shipping Company packages their shipments in 50 ton containers. History has shown that the shipping department reports that the distribution of container weights follows the normal distribution
1.a researcher was interested in determining whether incentives and how they were offered affected the response rate in
q1 the weights of packets of cookies produced by a manufacturer have a normal distribution with mean 202 grams and
determine a 95 confidence estimate for the mean time between failures mtbf of a power supply. we have 200000 hours
hen investigating a relationship between birth weight and IQ, researchers found that 258 subjects with extremely low birth weights (less than 1000 g) had Wechsler IQ scores at age 8 with a mean of 95.5 and a standard deviation of 16.0.
Of those not having lung disease, 25.3% are smokers. Determine the probability that a randomly selected smoker has lung disease.
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