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A 1270-kg car travels 1.19 km up an incline at constant velocity. The incline has an angle of 2.19° with respect to the horizontal.
A.)What is the change in the car's potential energy?
I got this part by doing U = mgL -----> U = (1270)(9.81)(1190sin2.19) = 0.567 MJ but I can't get this one for the life of me.
B.)What is the net work done on the car?
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