A 1270-kg car travels 119 km up an incline at constant

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A 1270-kg car travels 1.19 km up an incline at constant velocity. The incline has an angle of 2.19° with respect to the horizontal.

A.)What is the change in the car's potential energy?

I got this part by doing U = mgL -----> U = (1270)(9.81)(1190sin2.19) = 0.567 MJ but I can't get this one for the life of me.

B.)What is the net work done on the car?

Reference no: EM13584908

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