2als3cl2ggt2alcl3syou are givennbsp300nbspg of aluminum

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Reference no: EM13642847

Aluminum reacts with chlorine gas to form aluminum chloride via the following reaction:
2Al(s)+3Cl2(g)>2AlCl3(s)You are given 30.0 g of aluminum and 35.0 g of chlorine gas.If you had excess chlorine, how many moles of of aluminum chloride could be produced from 30.0 g of aluminum?

Reference no: EM13642847

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2als3cl2ggt2alcl3syou are givennbsp300nbspg of aluminum : aluminumnbspnbspreacts with chlorine gas to form aluminum chloride via the following reaction2als3cl2ggt2alcl3syou are

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