Voltage Divider Bias Assignment Help

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Biasing the Field Effect Transistor

Voltage Divider Bias :

The biasing circuit is based on the single power supply is shown in the figure 1. This is like the voltage divider bias used with the bipolar transistor.

1657_voltage divider bias.png

Figure 1

The Thevenin voltage VTH which is applied to the gate is

1895_voltage divider bias1.png

The Thevenin resistance can be given as

2206_voltage divider bias2.png

The gate current is supposed to be negligible. VTH is the DC voltage from gate to ground.

1558_voltage divider bias3.png

The drain current ID can be given by

253_voltage divider bias4.png

and the dc voltage from the drain to ground is VD = VDD - ID RD.

If the value of VTH  is large enough to swamp out VGS  the drain current is approximately constant for any JFET as shown in the figure 2.

2424_voltage divider bias5.png

Figure  2

There is a problem in JFET. In a BJT, VBE  is approximately 0.7V, with only minor variations from one transistor to other. In the FET, VGS can vary some volts from one JFET to another. It is thus, difficult to make VTH large enough to swamp out VGS. For this very reason, the voltage divider bias is less effective with, FET than the BJT. Hence, VGS is not negligible. The current increases slightly from Q2 to Q1. However, voltage divider bias maintains ID nearly constant.

Consider the voltage divider bias circuit as shown in the figure 3.

 

1864_voltage divider bias6.png

88_voltage divider bias7.png

Difference in ID (min) and ID (max) is less

VD (max) = 30 - 2.13 * 4.7 = 20 V VD (min) = 30 - 2.67 * 4.7 = 17.5 V

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