Undecidable problems:
Given a TM T, is L(T) finite?
Guess FINITE is neither R.E. nor co-R.E.
- To assure L(T) is finite, we require to run T on all the possible input and count if T accepts the finite number of strings.
- To assure L(T) is infinite, we require to run T on all possible input and count if T accepts the infinite number of strings.
FINITE is not recursive FINITE is not recursive
Let FINITE={<T>| T is a TM such that L(T) is finite.} Guess FINITE is neither R.E. nor co-R.E.
Choose NSA which is not co-R.E. to show that NSA≤FINITE.
We want to find a Turing-computable function f so that <T>∈NSA « f(<T>)=M∈FINITE
<T>∈NSA -> M accepts Φ, and thus L(M) is finite.
<T>∈NSA ->M accepts Σ*, and thus L(M) is infinite.
Then, let M=f(<T>) be a TM which runs T on its input, and accepts everything if T stops.
FINITE is not recursive
Now, we will show that <T>∈NSA ↔ <M>∈FINITE
If <T>∈NSA, then T does not accept <T>. Then, M does not get to begin AccAll. Therefore, M accepts nothing and L(M) is finite.
If <T>∈NSA, then T accepts <T>. Then, M gets pass T, and accept everything. Therefore, M accepts
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