Torque Assignment Help

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Torque of a force about the axis of rotation: The turning effect of a force about the axis of rotation is known moment of force or torque due to the force and is measured as the product of the magnitude of the force and the perpendicular distance of the line of action of the force from the axis of rotation.

2132_Torque.png

It is given by the Greek letter tou. Thus, torque = force * perpendicular distance from the axis of rotation

Its unit is N m in SI. Its dimensional formula is [M L2 T-2], similar as that of work. It can be pointed out that no doubt, N m is equivalent to joule; but joule is not used as the unit of torque.    

Suppose a force 2241_Torque1.png performing on a particle P. select an origin O and let 1079_Torque2.png be the position vector of the particle experiencing the force. We describe the torque of the force F about O as ,1735_Torque3.png         ... (1)

This is a vector quantity having its direction perpendicular to 1079_Torque2.png  and 2241_Torque1.png  according to the principle of cross product. Now take a rigid object rotating about a given axis of rotation AB (fig b). Let F be a force operating on the particle O of the body. F cannot be in the plane ABP. Take the origin O somewhere on the axis of rotation.

1776_Torque4.png

The torque of F about O is 1735_Torque3.png . Its element along OA is known the torque of 2241_Torque1.png about OA. To determine it, we could find the vector 1079_Torque2.png*2241_Torque1.png  and then find out the angle θ it creates with OA. The torque about OA is then 1850_Torque5.png . Let O1 be any point on the line AB. The torque of F about O1 is

1741_Torque6.png                          

As 588_Torque7.png this term will have no element along AB.

Thus, the component of 357_Torque8.png is equal to that of 357_Torque8.png 

 

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