Step invariant design Assignment Help

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Step invariant design Here the result of the digital filter to the unit step sequence, u(n), is selected to be samples of the analog step response. In that way, if the analog filter has good step response properties, such as small rise-time and low peak over-shoot, these characteristics could be saved in the digital filter. Clearly this idea of waveform invariance may be extended to the preservation of the output wave type for a variety of inputs.

253_Step invariant design.png

(Omit) Problem Given the analog that system Ha(s), let ha(t) be its impulse response and let pa(t) be its step response. The system Ha(s) is provided to be continuous-time linear time-invariant.                                                  

h(n) be the unit sample response,

p(n) be the step response, and,

H(z) be the system function,

of a discrete-time linear shift-invariant filter. Then,

93_Step invariant design1.png

Solution (a) If h(n) = ha(nT), does 653_Step invariant design2.png? We know that

328_Step invariant design9.png

This is seen to be true by writing it out in full as

u(n) = δ(- ∞ ) + δ(- +1) + ...+ δ(-1) + δ(0) + δ(1) +...+ δ(n)

where n is implicitly various positive integer. Take, for instance, n = 3; then, from the above equation u(3) = δ(0) = 1, all the other terms being zero. In other words u(n) is a linear combination of unit type sample functions. And, since the response to δ(k) is h(k), therefore, the response to u(n) is a linear combination of the unit sample results h(k). That is,

653_Step invariant design2.png

Therefore, the answer to the above question is, Yes.

(b) If p(n) = pa(nT), does h(n) = ha(nT)? Since δ(n) = u(n) - u(n-1), the response of the digital system, H(z), to the input δ(n) is

h(n) = p(n) - p(n-1) = pa(nT) - pa(nT-T) ≠ ha(nT)

Therefore, the answer to the above example is, No.

 

Example [LP filter] [Step Invariance]

 Consider the continuous- time system Ha(s) A / s + a with unit step response pa(t). Calculate the system function, H(z), i.e., the z-transform of the unit sample response h(n) of a discrete-time system defined from this system on the types of step-invariance, such that p(n) = pa(nT), where

2005_Step invariant design3.png


Solution Since 389_Step invariant design10.png we have

271_Step invariant design4.png

where K1 and K2 are the coefficients of the partial fraction expansion, given by

2347_Step invariant design6.png

from which we show p(n) = pa (nT ) and hence P(z) etc. Equivalently, we can reason as follows. The correspondence between s-plane poles and z-plane poles is 

1987_Step invariant design7.png

However, what we need is H(z). Since δ(n) = u(n) - u(n-1), and we know the result to u(n), therefore, the response to u(n) - u(n-1) is provided by h(n) = p(n) - p(n-1), and taking the z- transform of this last relation,

1601_Step invariant design8.png

Alternatively, we can also obtain the transfer function as the ratio of input and output transforms, H(z) = P(z)/U(z).

 

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