Source Transformation
In an electric circuit, it is often convenient to have a voltage source rather than a current source (for example in mesh analysis) or vice versa. This is made possible by using source transformations. It should be kept in mind that only practical voltage and current sources can be transformed. In other words, a Thevenin's equivalent circuit is transformed into a Norton's 1 or vice versa. The parameters used in source transformation are given as follows.
Any load resistance, RL will have the same voltage across, and current through it when connected across terminals of either source.
Example
In Figure drawn below, use repeated source transformation to determine current through resistance.
The voltage source and resistor are in series, transform combination into the current source in parallel with resistor. The magnitude of the current source is calculated as follows
The resulting schematic is depicted in Figure 3.18(a). Now the 10Ω and 20Ω resistors are in parallel which can be combined together to form a single resistance of 6.67. This resistance will be in parallel with the 1 A current source which can be transformed back to a voltage source in series with the 6.67 resistance resulting in the single loop as shown in Figure 3.18(c). KVL can be applied to obtain the loop current which is same current fiowing through the resistor. Thus
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