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Biasing the Field Effect Transistor

Self Bias:

1286_self bias.png

Figure 1, shows a self bias circuit another manner by which we can bias a FET. The drain supply is used only and no gate supply. The basic idea is to make use the voltage across RS to produce the gate source reverse voltage.

This is the form of a local feedback which is similar to that which we use with bipolar transistors.  If we increases drain current, the voltage drop across RS increases as the ID RS increases. This increases gate source reverse voltage which makes the channel narrow and reduces drain current.  The overall effect is to offset the original increase in drain current. Likewise, if ID Figure 1 decreases, drop across RS decreases, hence the reverse bias decreases and ID increases.

As the gate source junction is made reverse biased, negligible the gate current flows through RG and so the gate voltage with respect to the ground is zero.

VG= 0;

The source to ground voltage equals the product of drain current and source resistance.

\ VS= ID R S.

The gate source voltage is difference in between the gate voltage and the source voltage. VGS = VG - VS = 0 - IDRS

VGS = -ID RS.

This means that the gate source voltage equals the negative of the voltage across the source resistor. The greater the value of drain current, more negative the gate source voltage becomes.

By rearranging the equation: ID = -VGS / RS

The graph of this equation is called as self base line a shown in the figure 2.

1803_self base line.png

Figure 2

The operating point on the transductance curve is intersection of the self  bias  line  and  transductance  curve. The slope of line is (-1 / RS). If the source resistance is large (-1 / RS  is small) then Q-point is far down the transductance curve and drain current is small. When the value of RS is small, the Q point is far up the transductance curve and drain current is large. In between there exist an optimum value of RS  which sets up a Q point near the middle of the transductance curve.

The transductance curve ranges widely for FET (due to the variation in IDSS and VGS(off)) as shown in the figure 3.  The actual curve can be between there extremes. A and B are optimum points for the 2 extreme curves. To find out the optimum resistance RS, so that the Q-point is accurate for all the curves, A and B points are joined so that it passes through the origin.

The slope of this line provides the resistance value RS( VGS = -ID RS). The current IQ is such that IA > IQ > IB. Here A, Q and B all points are in the straight line.

 

1945_operating point of transductance curve.png

Fig. 3

By taking the case where a line drawn to pass in between points A and B does not pass through the origin. The equation VGS = - ID RS is not appropriate. The equation of the line is VGS = VGG - ID RS.

This type of a bias relationship can be obtained by adding a fixed bias to the gate in addition to the source self bias as shown in the figure 4.

835_operating point of transductance curve1.png

Figure 4

In the circuit

VGG = RS IG + VGS + ID RS

Since RS IG = 0;

VGG = VGS + ID RS

or     VGS = VGG- ID RS

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