Properties of binomial coefficient:
For the sake of expediency the coefficients nC0 , nC1 , . . ., nCr , . . . ,nCn are generally denoted by C0, C1 , . . . , Cr , . . . ,Cn respectively
- C0 + C1 + C2 +. . . . . + Cn = 2n
- C0 - C1 + C2 -. . . . . + (-1)n Cn = 0
- C0 + C2 + C4 +. . . . . = C1 + C3 + C5 +. . . . . = 2n-1
- nCr1 + nCr2 => r1 = r2 or r1 + r2 = n
- nCr + nCr-1 = n+1Cr
- r nCr =n n-1Cr-1
- .
Problem: Calculate the value of
Solution: The provided value is
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