Pair of straight lines:
The general equation of 2nd degree ax2 + 2hxy + by2 + 2gx + 2fy + c = 0 represents the pair of straight lines if and h2 ≥ ab.
=> abc + 2fgh - af2 - bg2 - ch2 = 0 and h2 ≥ ab.
The homogeneous 2nd degree equation ax2 + 2hxy + by2 = 0 represents the pair of straight lines through the origin if h2 ≥ ab.
If lines through the origin whose joint equation is ax2 + 2hxy + by2 = 0, are y = m1x and
y = m2x, then y2 - (m1 + m2)xy + m1m2x2 = 0 and are identical, such that
.
If q be the angle between 2 lines, through the origin, then
The lines given are perpendicular if a + b = 0 and coincident if h2 = ab.
The joint Equation of Pair of Lines Joining the Origin and the Points of Intersection of the Curve and a Line:
If line lx + my + n = 0, ((n ¹ 0) that is the line does not pass through origin) cut the curve ax2 + 2hxy + by2 + 2gx + 2fy + c = 0 at 2 points A and B, then joint equation of the straight lines passing through A and B and the origin can be given by homogenizing the equation of the curve by the equation of line. That is
is the equation of lines OA and OB
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Illustration: If lines joining origin to the points of intersection of curve 2x2 + 3y2 + m = 0 and the line y = 2x + 3 are perpendicular, and then find the value of m.
Solution. Homogenise given curve with the line, we get the desired line
As, the lines are perpendicular
=> Coefficient of x2 + coefficient of y2 = 0
=> m = -9
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