It is an optical instrument used to see very small bodies. Its magnifying energy is provided by

(iv) If lens is placed at a distance a from the eye then 

(v) u_o= Distance of object from objective(o), v_o = Distance of image (A'B') formed by objective from objective, u_e = Distance of A'B' from eye lens, v_e  = Distance of final image from eye lens, f_o = Focal length of objective, f_e = Focal length of eye lens.

(vi) Final image is formed at ∞: Magnification  and length of the microscope tube (distance between two lenses) is L_D = u_o + v_e .

Generally object is placed very near to the principal focus of the objective hence u_o≡f_o  . The eye piece is also of small focal length and the image formed by the objective is also near to the eye piece.

            So v_o≡ L_D , the length of the tube.

Hence, we can write 

(vii) Final image is formed at : magnification   and length of tube  L_∞ = v_o + f_e

            In terms of length 

(viii) For larger magnification of the compound microscope, both f₀  and f_e  should be small.

(ix) If the size of the tube of microscope increases, then its magnifying power increases.

(x) The magnifying energy of the compound microscope may be expressed as M = m_o *  m_e ; where m_e is the magnification of the objective and m_e is magnifying power of eye piece.

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