Nucleus Assignment Help

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The nuclei have been divided on the basis of the number of protons (atomic number) or the total number of nucleons (mass number) as follows

(i) Isotopes: The atoms of element having same atomic number but different mass number are known as isotopes. All isotopes have the similar chemical properties. The isotopes of similar components are the following

 

706_Nucleus.png

(ii) Isobars: The nuclei which have the same mass number (A) but different atomic number (Z) are called isobars. Isobars occupy different positions in periodic table so all isobars have different chemical characteristics. Some of the types of isobars are

 

176_Nucleus1.png

(iii) Isotones: The nuclei having equal number of neutrons are called isotones. For them both the atomic number (Z) and mass number (A) are different, but the value of (A - Z) is same. Some examples are

 

2126_Nucleus2.png

(iv) Mirror nuclei: Nuclei having the same mass number A but with the proton number (Z) and neutron number (A - Z) interchanged (or whose atomic number differ by 1) are called mirror nuclei for example.

 

764_Nucleus3.png

Size of nucleus:

(i) Nuclear radius: Experimental results indicate that the nuclear radius is related to A1/3, where A is the volume number of nucleus i.e.     741_Nucleus4.png

(ii) Nuclear volume: The mass of nucleus is shown by 554_Nucleus5.png

(iii) Nuclear density: Volume per unit mass of a nucleus is called nuclear density.

394_Nucleus6.png

where m = Average of mass of a nucleon (= mass of proton + mass of neutron = 1.66 * 10-27 kg)  and mA = Mass of nucleus

Pair production and pair-annihilation:

When an energetic y-ray photon falls on a heavy materials. It is absorbed by few atoms of the substance and an electron and a positron are given. This process is known as pair production and may be represented by the following equation         

564_Nucleus9.png

 

593_Nucleus8.png

The rest-mass power of every of positron and electron is

            E0 = m0c2 = (9.1 * 10-31 kg) * (3.0 * 108 m/s)2

                 = 8.2 * 10-14 J = 0.51 MeV

Hence, for pair-production it is essential that the energy of g-photon must be at least 2 ´ 0.51 = 1.02 MeV. If the energy of g-photon is less than this, it would create problem photo-electric effect or Compton Effect on striking the matter.

The converse phenomenon pair-annihilation is also possible. Whenever an electron and a positron get very close to one another, they annihilate one another by combining together and two g-photons (energy) are given. This process is known as pair annihilation and is represented by the following equation.

1540_Nucleus10.png

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