Linear Differential Equation having constant coefficient Assignment Help

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Linear Differential Equation having constant coefficient:

Differential equation of the form 336_Linear Differential Equation having constant coefficient.png n is  called   as linear  differential equation   having  constant  coefficients.

In order to solve this differential equation, take auxiliary equation as a0Dn + a1Dn-1 +...+ an =0

Find out the roots of this equation and then solution of given differential equation will be as given in following table

1384_Linear Differential Equation having constant coefficient1.png

Theorem:

If  y = f1(x) is general solution of 1721_Linear Differential Equation having constant coefficient3.png

and  y = f2(x)  is a solution of

2160_Linear Differential Equation having constant coefficient4.png

Then y = f1(x) + f2(x) is general solution of 2160_Linear Differential Equation having constant coefficient4.png

Expression f1(x)  is called as complementary function and the expression f2(x) is called as specific integral. These can be denotes by C.F.  and P.I. respectively.

The nth derivative of y can be denoted Dny where D stands for d/dx and n denotes the order of derivative.

If we take the Differential Equation:

1346_Linear Differential Equation having constant coefficient5.png

then we can write this differential equation in a symbolic form as

Dny + P1Dn- 1y + P2Dn- 2y + ....+ Pny = X

(Dn + P1Dn- 1 + P2Dn- 2 + ....+ Pn)y = X

The operator Dn + P1Dn- 1 + P2Dn- 2 + ....+ Pn­ can be denoted by f(D) so that the equation takes the form f(D)y = X

y = 1/f(D) x

Methods of finding P.I. :

Notes:            

If m1 and m2 both are constants, the expressions (D - m1)(D - m2)y and (D- m2)(D - m1)y are equivalent that is the expression is independent of the order of operational factors.

52_Linear Differential Equation having constant coefficient6.png

            We will explain method with the help of following example

Example: Solve 1832_Linear Differential Equation having constant coefficient7.png.

Solution:         The equation can be given as (D2 - 5D + 6)y = e3x

                        (D - 3) (D - 2)y = e3x

                      2262_Linear Differential Equation having constant coefficient8.png                   

                        Into partial functions

                     2439_Linear Differential Equation having constant coefficient9.png

 

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