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Inverse DFT using the FFT algorithm

The inverse DFT of the N-point sequence {X(k), k = 1, 2, ... , (N-1)} can be defined as

1769_Inverse DFT using the FFT algorithm.png,   

here 147_Inverse DFT using the FFT algorithm1.png. Take complex conjugate of x(n) and multiply by N to obtain 2081_Inverse DFT using the FFT algorithm2.png

 

The right hand side of above equation is simply DFT of the sequence X*

(k) and can be calculated by using any FFT algorithm. The output sequence which is desired is then found by taking the conjugate of result and dividing by N  1148_Inverse DFT using the FFT algorithm3.png 


Example Given DFT sequence X(k) = {0, (-1-j), j, (2+j), 0, (2-j), -j, (-1+j)} obtain the IDFT x(n) by using the DIF FFT algorithm.

Solution

This is an 8 point IDFT. The 8 point twiddle factors are, as computed earlier,

1110_Inverse DFT using the FFT algorithm4.png 
The elementary computation (Butterfly) is shown as follows:

715_Inverse DFT using the FFT algorithm5.png 

The signal flow graph id drawn as follows:
772_Inverse DFT using the FFT algorithm6.png 


385_Inverse DFT using the FFT algorithm7.png

1199_Inverse DFT using the FFT algorithm8.png 

2265_Inverse DFT using the FFT algorithm9.png 

The output at the stage 3 gives us values 2052_Inverse DFT using the FFT algorithm10.pngin bit-reversed order:

937_Inverse DFT using the FFT algorithm11.png

The IDFT can be given by arranging the data in normal order, taking complex conjugate of the

sequence and dividing it by 8:

768_Inverse DFT using the FFT algorithm12.png

Because of the conjugate symmetry of {X(k)}, we should expect sequence {x(n)} to be

real-valued.

The MATLAB program:
678_Inverse DFT using the FFT algorithm13.png 

Example 3.4.2 Given DFT sequence X(k) = {0, (1-j), j, (2+j), 0, (2-j), (-1+j), -j}

obtain IDFT x(n) using the DIF FFT algorithm.

Solution
There exists no conjugate symmetry in {X(k)}. By using MATLAB

952_Inverse DFT using the FFT algorithm14.png 

The IDFT is
x(n) = {0.5, (-0.44 + 0.037i), (0.375 - 0.125i), (0.088 + 0.14i), (-0.75 + 0.5i),

(0.44 + 0.21i), (-0.125 - 0.375i), (-0.088 - 0.39i)}

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