Formation of differential Equation:
We know y2 = 4ax is a parabola whose vertex is origin and axis as the x-axis . If a is a parameter, it represents a family of parabola with the vertex at (0, 0) and axis as y = 0 .
Differentiating y2 = 4ax . . (1)
. . (2)
From equation (1) and (2),
This is a differential equation for all the members of family and it does not contain any parameter .
(i) The differential equation of a family of curves of one parameter is the differential equation of the 1st order, which is obtained by eliminating the parameter by differentiation.
(ii) The differential equation of a family of curves of 2 parameter is a differential equation of the 2nd order, which can be obtained by eliminating the parameter by differentiating the algebraic equation twice. Similar process is used to find out differential equation of a family of curves of 3 or more parameter.
Example Find differential equation of the family of curves y = Aex + Be3x for different values of A and B.
Solution: y = A ex + Be3x . . . . (1)
y1 = Aex + 3Be3x . . . (2)
y2 = Aex + 9B3x . . . (3)
By eliminating A and B from the above 3, we get
=> 3y + 4y1 - 4y2 = 0 =>
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