Given a particle moving along a straight line with fixed acceleration a. Let u be the initial velocity of the particle and v be the velocity at time t. So by definition,
a = dv/dt dv = a dt
Integrating,
(a being a constant may be taken out of the integral) v - u = at
v = u + at ...(i)
Further, v = dx/dt dx = vdt
But, v = u + at, dx = (u + at)dt
Integrating within limits, equations change into,
...(ii)
Again, going back to definition of acceleration, we have, a = dv/dt
Multiply and divide RHS of above equation by dx, equation gets,
a = v(dv/dx) adv = adx
Integrating within limits, equation converts,
v2/2-u2/2 = a(s-0) v2-u2 = 2as ...(iii)
From (i) and (iii) we also result that, ...(iv)
Equation (iv) is a special equation, as we do not have a in this equation, but still it belongs to motion, which is uniformly accelerated.
To result, we again write the equation of motion for constant acceleration below.
v = u + at;
s = at + 1/2at2;
v2 - u2 = 2as;
s = {(u+v)/2}*t
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