Equation of Tangents from an External Point Assignment Help

Assignment Help: >> Tangent to a parabola >> Equation of Tangents from an External Point

Equation of Tangents from an External Point:

Let y2 = 4ax be equation of a parabola and (x1, y1) an external point P. Then, equations of tangents from (x1, y1) to given parabola are given by

SS1 = T2, here S = y2 - 4ax, S1 = y12 - 4ax1, T = yy1 - 2a(x + x1)

Chord of Contact:

Equation to chord  of  contact of  the tangents  drawn  from  the  point  (x1, y1), to parabola  y2= 4ax is T= 0, that is yy1 - 2a(x+x1) =0.

Equation of a Chord with Midpoint (x1, y1):

The equation of chord of the parabola y2= 4ax having mid point (x1, y1) is T= S1

i.e.    yy1-2a(x+x1)= y12-4ax1 Or yy1 - 2ax = y12 - 2ax1 .

Example: Find equation of chord of the parabola y2 = 12x which is bisected at the point (5, -7).

Solution:        Here (x1, y1) = (5 -7) and y2 = 12x, ∴a = 3

                        The equation of chord is S1 = T

                        or y12- 4ax1 = yy1 - 2a (x + x1)

                        or (-7)2 - 12.5 = y(-7) - 6(x+5)

                        => 6x + 7y + 19 = 0.

 

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