Equation of tangents:
Definition of tangent: The tangent at any point of the circle if defined to be straight lines which meet the circle at that particular point but being produced, does not cut it at all. The point where tangent meets the curve is called the point of contact.
- Equation of the tangent to x2 + y2 + 2gx + 2fy + c = 0 at (x1 , y1) is given by xx1 + yy1 + g(x + x1) + f(y + y1) + c = 0.
- The condition that the straight line y = mx + c is a tangent to the circle x2 + y2= a2 is c2 = a2 (1 + m2) and the point of contact is (-a2m/c, a2/c) i.e. y = mx ± a √1+m2 is always a tangent to the circle x2 + y2 = a2 whatever be the value of m.
Illustration: Find the locus of the point of intersection of tangents to the circle x2 + y2 =4 which are at right angle to each other.
Solution: Let point of intersection be ( h , k) . Equation of any tangent
y = mx + 2 √1+m2
This passes through ( h ,k)
K - mh = 2 √1+m2
=> (h2 - 4 ) m2 - 2 khm + k2 - 4 = 0. Roots of the equation will represent slope of the tangents drawn from point (h, k). Let the roots be m1 and m2. Now both tangents are perpendicular to each other
=> m1.m2 = - 1 => k2-4/h2-4 => h2 + k2 = 8
Alternate solution
![2192_Equation of tangents.png](https://www.expertsmind.com/CMSImages/2192_Equation%20of%20tangents.png)
From diagram it is clear that
ACBP will be a square
Hence CA2 + AP2 = CP2
=> h2 + k2 = 4 + 4
Therefore the locus is x2 + y2 = 8
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