Differentiation:
Let f (x) be the real valued function defined on the open interval (a,b) where c ∈ (a,b) Then f (x) is said to be differentiable or derivable at the point x = c,
exists finitely.
This limit is called as derivative or differential coefficient of function
f(x) at x = c, and can be denoted by f'(c) or D f (c) or d/dx (f (x))x = c
<=>Therefore, f (x) is differentiable at x = c
exists finitely
Here is called as left hand derivative of f (x) at x = c and is denoted by f'(c-) or LF'(c).
While , iis called as right hand derivative
of f (x) at x=c and can be denoted by f' (c+)or Rf' (c).
Therefore f (x) is differentiable at x = c.
Lf'(c) = Rf' (c)
If Lf' (c) ≠ Rf'(c) then f (x) is not differentiable at x = c.
Example : The set of triplets (a, b, c) of real numbers having a ≠0, for which the function
f(x) = , is differentiable, is
(A) { ( a, 1- 2a, a) / a ∈R; a ≠ 0 }
(B) { ( a, 1- 2a, c) /a, c ∈R; a ≠ 0 }
(C) { (a, b, c)/ a, b, c ∈R; a + b+ c = 1 }
(D) { ( a, 1- 2a, 0) / a ∈R; a ≠ 0 }
Solution: (A) Given that the f is differentiable for all the real x
=> f is continuous for all the real x.
so, f(x) = f(1) => a + b + c =1 . . . . (1)
Also f'(x) =
f' (1+) = f'(1-) => 1 = 2a + b => b = - 2a + 1 . . . . (2)
as a, b, c ∈ R and a ≠ 0, using (1) and (2)
=> c = a
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