Calculations of Volumetric analysis

         The following points should be reminded while making calculations of volumetric exercises.

         (i) 1g equivalent mass of a substance performs completely with 1g equivalent mass of any other substance. 1g equivalent mass of a substance means equivalent mass of the substance in grams. For example,

         1g equivalent mass of NaOH = 40 g of NaOH

         1g equivalent mass of H₂SO₄ = 49 g of H₂SO₄

         1g equivalent mass of KMnO₄ in acidic medium = 31.6 g of KMnO₄

         1g equivalent mass of hydrated oxalic acid = 63 g of hydrated oxalic acid

         Note : Equivalent mass is a variable quantity and depends on the reaction in which the substance takes part. The nature of the reaction should be known before writing the gram equivalent mass of the substance. For example in the reactions.

         The value of g equivalent mass of H₂SO₄ in reaction (i) is 98 g and in reaction (ii) 49g.

(ii) Number of g equivalents

         Number of g moles 

           (only for gases)

         Number of milli-equivalent 

         Number of milli-moles 

         (iii) Molarity   

         Molarity * molecular mass = strength of the solution (g/L) No. of moles of the solute = Molarity * No. of litres of solution Mass of the solute in g(w) =molarity * No. of litres of solution * mol. mass of solute

         Normality   

         Normality * equivalent mass = strength of the solution (g/L)

         No. of equivalents of the solute = Normality * No. of litres of solution

         Mass of the solute in g(w) = Normality * No. of litres of solution * Eq. mass of the solute

         Normality = n * Molarity

         (iv) Normality equation : When solutions A and B react completely.

         N_AV_A = N_BV_B

         Normality of A * volume of A = Normality of B * volume of B

         (v) When the solution is diluted, the following formulae can be applied:

         N₁V₁ = N₂V₂ or M₁V₁ = M₂V₂ or S₁V₁ = S₂V₂

         Before dilution = After dilution

         (vi) If a number of acids are mixed, the combined normality of the mixture, Nx, is provided

         NxVx = N₁V₁ + N₂V₂ + N₃V₃ +.......

         Where Vx is the total volume of the mixture, N₁ and V₁ are the normality and volume respectively of one acid, N₂ and V₂ of the second acid and so on.

Email based Chemistry assignment help - homework help at Expertsmind

Are you searching chemistry expert for help with Calculations of Volumetric analysis questions?  Calculations of Volumetric analysis topic is not easier to learn without external help?  We at www.expertsmind.com offer finest service of Chemistry assignment help and chemistry homework help. Live tutors are available for 24x7 hours helping students in their Calculations of Volumetric analysis related problems. We provide step by step Calculations of Volumetric analysis question's answers with 100% plagiarism free content. We prepare quality content and notes for Calculations of Volumetric analysis topic under chemistry theory and study material. These are avail for subscribed users and they can get advantages anytime.

Why Expertsmind for assignment help

1. Higher degree holder and experienced experts network
2. Punctuality and responsibility of work
3. Quality solution with 100% plagiarism free answers
4. Time on Delivery
5. Privacy of information and details
6. Excellence in solving chemistry queries in excels and word format.
7. Best tutoring assistance 24x7 hours