Bisectors of angle between two given lines:
Say a1x+b1y+c1 = 0........(1)
a2x + b2y + c2 = 0....(2) are the 2 intersecting lines.
Let any point p(x, y) be any point on the 2 bisectors of angles of (1) and (2).
Then p is equidistance from (1) and (2)
that are the required equations of the 2 bisectors of angles between (1) and (2).
If the 2 given lines are not perpendicular that is a1 a2 + b1 b2 ≠ 0, then one of these equation is the equation of the bisector of acute angle and the other that of the obtuse angle.
The equation of acute and obtuse angle bisectors:
Method 1
Step 1: Take 1 of the given lines and let the slope of it be m1 and take one of the bisectors and let it is slope be m2.
Step 2: If θ is the acute angle between them, then find the value of
Step 3: If tanθ > 1 then bisector taken is the bisector of the obtuse angle and other one will be the bisector of acute angle.
If tanθ < 1 then bisector taken is the bisector of the acute angle and other one will be the bisector of obtuse angle.
Method 2:
If the constant term c1 and c2 in the 2 equations a1x+b1y+c1 = 0 and a2x + b2y + c2 = 0 are having same sign, then
Case 1: if will be the equation of obtuse angle bisector and
will be the equation of acute angle bisector.
Case 2: if will give equation of the acute angle bisector and
will give the equation of the obtuse angle bisector.
Note: Whether both lines are perpendicular to each other or not but the angle bisectors of these lines will always be mutually perpendicular.
The equation of bisector of angle which has a given point:
The equation of bisector of angle between the 2 lines containing point (α, β) is
are having same signs
or are having opposite signs
The equation of bisector of angle containing the origin:
Write down the equations of the 2 lines so that constants c1 and c2 are positive. Then the equation
is the equation of the bisector containing origin.
Note: if a1a2 + b1b2 < 0, then origin will lie in acute angle and if a1a2 + b1b2 > 0 then origin will lie in obtuse angle.
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