Arithmetico-geometric progression:
Consider a1, a2, a3......is an Arithmetic progression. and b1, b2, b3..... is a G.P. Then the series a1b1, a2b2, ....... is called to be an arithmetico-geometric progression (A.G.P). Consequently an arithmetico-geometric progression is of the one of the form ab, (a+d)br, (a+2d)br2, (a+3d)br3,.........
Summation of n Terms:
The addition Sn of first n terms of an A.G. P. is calculated in the given way :
Sn = ab + (a + d)br + (a + 2d)br2 +.........+(a + (n - 2)d)brn-2 + (a + (n - 1)d)brn-1
Multiply each sides by r, so that
r Sn = abr + (a + d)br2+.........+(a + (n - 3)d)brn-2 + (a + (n - 2)d)brn-1 + (a + (n - 1)d)brn
Subtracting, we obtain
(1 - r)Sn = ab + dbr + dbr2 +.......+dbrn - 2 + dbrn - 1 - (a + (n - 1)d)brn
![1431_Arithmetico-geometric progression.png](https://www.expertsmind.com/../CMSImages/1431_Arithmetico-geometric progression.png)
If -1 < r < 1, the summation of the infinite number of terms of the progression is
![1826_Arithmetico-geometric progression1.png](https://www.expertsmind.com/../CMSImages/1826_Arithmetico-geometric progression1.png)
Problem: Calculate the sum of the series 1.2 + 2.22 + 3.23 + ..... + 100.2100.
Solution: => = 1.2 + 2.22 + 3.23 + .... + 100.2100
2S =1.22 + 2.23 + .... + 99.2100 + 100.2101
=> -S = 1.2 + 1.22 + 1.23 + .... + 1.2100 - 100.2101
= -2101 + 2 + 100.2101 = 99.2101 + 2.
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