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Application of Le-Chatelier's principle

The Le-Chateliers principle has a great significance for the chemical, physical systems and in day to day life in a state of equilibrium.

(1) The applications to chemical equilibrium

(i) Synthesis of ammonia (Haber's process)

  1767_application of le chatelier law.png   (exothermic)

(a) High pressure ( Δn <0)

(b) Low temperature

(c) Excess of N2 and H2

(d) Removal of NH3 favours forward reaction.

(ii) Formation of sulphur trioxide

1457_application le chatelier law1.png   (exothermic)

(a) High pressure ( Δn<0)

(b) Low temperature

(c) Excess of SO2 and O2, favours the reaction in forward direction.

(iii) Synthesis of nitric oxide

  956_application le chatelier law2.png   (endothermic )

(a) High temperature

(b) Excess of N2 and O2

(c) Since reaction takes place without change in volume i.e., Δn=0, pressure has no effect on equilibrium.

(iv) Formation of nitrogen dioxide

 1900_application le chatelier law3.png

(a) High pressure

(b)Low temperature

(c) Excess of NO and O2 favors the reaction in forward direction.

(v) Dissociation of the phosphorus pentachloride

801_application le chatelier law4.png

(a) The low pressure or high volume of container, Δn>0 

(b) High temperature
(c) Excess of PCl5

(2) The applications to physical equilibrium

(i) Melting of the ice (Ice - water system)

 58_application le chatelier law5.png

(In this reaction volume is decreased from the 1.09 cc to 1.01 cc per gm.)

(a) At the high temperature more water is formed as it absorbs the heat.

(b) At the high pressure more water is formed as it is accompanied by the decrease in volume.

(c) At the higher pressure, melting point of the ice is lowered, while the boiling point of water is increased.

(ii) Melting of sulphur :  2452_application le chatelier law6.png

(This reaction accompanies increase in volume.)

(a) At the high temperature, more liquid sulphur is formed.
         (b) At the higher pressure, less sulphur will melt as melting increases the volume.

(c) At the higher pressure, melting point of sulphur gets increased.

(iii) The boiling of water (water- water vapour system)
794_application le chatelier law7.png

(It is accompanied by the absorption of heat and increase in volume.)

(a) At the high temperature more vapours are formed.

(b) At the higher pressure, vapours will be converted into the liquid as it decreases volume.

(c) At the higher pressure, boiling point of water is increased (it is principle of the pressure cooker).

(iv) Solubility of salts: If solubility of a salt is accompanied by the absorption process of the heat, solubility of it increases with the rise in temperature; for example NH4Cl, K2SO4, KNO3 etc.

59_application le chatelier law8.png

On the other hand if it is accompanied by evolution of heat, solubility decreases with increase in temperature; for example CaCl2, Ca(OH)2, NaOH, KOH etc.

2176_application le chatelier law9.png

The relation which we can found between the vapour density and the  Degree of dissociation

In the below reversible chemical equation.

                            2067_application le chatelier law10.png

Initial mol                1                     0

At equilibrium  (1-x)                 yx        x = degree of dissociation

Number of moles of A and B at equilibrium = 1-x+yx = 1+x(y-1)

If initial volume of 1 mole of A is V, then volume of equilibrium mixture of A and B is, = [1+x(y-1)]V

Molar density before dissociation, 

1122_application le chatelier law11.png

Molar density after dissociation process ; 1078_application of le chatelier law12.png  ;

635_application of le chatelier law13.png

y is the number of moles of products from one mole of reactant. D/d is also called Van't Hoff factor.

In terms of molecular mass,    1930_application le chatelier law13.png

Where M = Initial molecular mass,  

 m = molecular mass at equilibrium 

Thus for the equilibria

669_application of le chatelier law14.png

Also D * 2= Molecular weight (theoretical value)

D * 2 = Molecular weight (abnormal value) of the mixture.

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