Angular momentum: The turning movement of a particle about the axis of rotation is known the angular momentum of the particle and is calculated as the product of the linear momentum and the perpendicular distance of its lien of operation from the axis of rotation. It is shown by L.
Therefore, Angular momentum = linear momentum * perpendicular distance from the axis of rotation
Angular momentum of a particle about a point:
Consider a particle A of mass m is moving with linear momentum
. Its angular momentum
about point 0 is shown as:
Here, is the radius vector of particle A about 0 at that instant of time. The magnitude of is
![1080_Angular momentum of a particle4.png](https://www.expertsmind.com/../CMSImages/1080_Angular momentum of a particle4.png)
Here, r= r sinΘ is the perpendicular distance of line of action of
Velocity from point O. The direction of is same as that of .
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![1405_Angular momentum of a particle14.png](https://www.expertsmind.com/../CMSImages/1405_Angular momentum of a particle14.png)
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Relation Between Torque and Angular Momentum
![1732_Angular momentum of a particle7.png](https://www.expertsmind.com/../CMSImages/1732_Angular momentum of a particle7.png)
This relation is analogous to
, which is applied in rotation.
Converstion of Angular momentum:
We know that ![2054_Angular momentum of a particle9.png](https://www.expertsmind.com/../CMSImages/2054_Angular momentum of a particle9.png)
When there is no net external torque acting on a particle, then ![2076_Angular momentum of a particle10.png](https://www.expertsmind.com/../CMSImages/2076_Angular momentum of a particle10.png)
Therefore, the angular momentum of the bodies remains invariant in the absence of any net external torque.
Angular Impluse:
The angular impulse of a torque in a required time interval is shown as ![141_Angular momentum of a particle11.png](https://www.expertsmind.com/../CMSImages/141_Angular momentum of a particle11.png)
Hence,
is the resultant torque performing on the system? Further, since
![2457_Angular momentum of a particle12.png](https://www.expertsmind.com/../CMSImages/2457_Angular momentum of a particle12.png)
Or
Thus, the angular impulse of the final torque is same to the change in angular momentum.
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