Aliasing and digital frequency Assignment Help

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Aliasing and digital frequency With Fs = 16 Hz the base band signal should be band-limited to 8 Hz. And we don't expect frequencies higher than 8 Hz. Consider the 3 signals x1(t), x2(t), and x3(t) of frequencies 4Hz, 12Hz and 28Hz, respectively, here x2 and x3?s frequencies are the aliases of x1?s. The continuous and discrete-time signals are given in the table below with the sampling rate of 16 samples/sec.

Aliasing and Digital Frequency

Analog frequency

Cycles/sec

Analog signal

Discrete-time signal

Digital frequency

Cycles/sample

4

x1(t) = cos 2π4t

x1(n) = cos 2π(1/4)n

0.25

12

x2(t) = cos 2π12t

x2(n) = cos 2π(3/4)n

0.75

28

x3(t) = cos 2π28t

x3(n) = cos 2π(7/4)n

1.75

8

x4(t) = cos 2π8t

x4(n) = cos 2π(1/2)n

0.5

16/3

x5(t) = cos 2π(16/3)t

x5(n) = cos 2π(1/3)n

1/3

If Nyquist criterion is to be satisfied (for the perfect signal reconstruction) we do not expect digital frequencies higher than 0.5 cycle/sample (or π rad./sample) in base band signal. This corresponds to taking two samples for every cycle (or digital frequency of half a cycle per sample) - the Nyquist criterion. The Digital frequencies higher than 0.5 cycle (x2(n)and x3(n) in this example) are actually not allowed.

When plotted x1(n), x2(n), and x3(n) can't be distinguished from one another for

the digital frequency. They all have a period = 4 and a frequency of 0.25 cycle per sample, and we know that x2(n) has a frequency of 0.75 cycle and x3(n) has a frequency of 1.75 cycle.

Generally any digital frequency above 0.5 cycle (π rad./sample) is an alias (or shows up as an alias of some base band frequency). It in fact has more cycles per sample than is apparent in a plot of sampled data.

The phenomenon of aliasing using the 2 waveforms x1(t), x2(t), and x3(t) and the corresponding sequences x1(n), x2(n), and x3(n) is demonstrated below.

 

In MATLAB:

%Aliasing demo

 

%First---------------------------------------------

%Plot the continuous-time waveforms x1(t), x2(t), and x3(t) over a 1-second interval t = 0: 1/500: 1;

x1 = cos (2*pi*4*t); %4 Hz

subplot(3, 1, 1), plot(t, x1, 'b');           %subplot(3, 1, 1) - 3 rows, 1 column, #1 xlabel ('Time, t, seconds'), ylabel('x1(t)');

title ('4 Hz')

grid;

 

x2 = cos (2*pi*12*t); %12 Hz

subplot(3, 1, 2), plot(t, x2, 'k');           %subplot(3, 1, 2) - 3 rows, 1 column, #2 xlabel ('Time, t, seconds'), ylabel('x2(t)');

title ('12 Hz')

 

x3 = cos (2*pi*28*t); %28 Hz

subplot(3, 1, 3), plot(t, x3, 'r');            %subplot(3, 1, 3) - 3 rows, 1 column, #3 xlabel ('Time, t, seconds'), ylabel('x3(t)');

title ('28 Hz')

 

%Second---------------------------------------------

%Plot the sequences x1(n), x2(n), and x3(n)

n = 0: 1: 16;

%4 Hz sampled at 16 Hz x1 = cos (n*pi/2);

subplot(3, 1, 1), stem(n, x1, 'bo');       %subplot(3, 1, 1) - 3 rows, 1 column, #1 xlabel ('Sample number, n'), ylabel('x1(n)');

title ('4 Hz at 16 samples/sec')

grid;

%12 Hz sampled at 16 Hz x2 = cos (3*n*pi/2);

subplot(3, 1, 2), stem(n, x2, 'ko');       %subplot(3, 1, 2) - 3 rows, 1 column, #2 xlabel ('Sample number, n'), ylabel('x2(n)');

title ('12 Hz at 16 samples/sec')

%28 Hz sampled at 16 Hz x3 = cos (7*n*pi/2);

subplot(3, 1, 3), stem(n, x3, 'ro');        %subplot(3, 1, 3) - 3 rows, 1 column, #3 xlabel ('Sample number, n'), ylabel('x3(n)');

title ('28 Hz at 16 samples/sec')

%---------------------------------------------

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