"AnswersQ1) P=F/A(500*10)/(0.5 *0.5)=20,000 N/m^2Q2) let pressure exerted by the woman be =P1 while for the elephant be =P2 P1=F/A= (80 * 10)/( ? *0.005^2)=10,185,916.36 N/m^2P2= (5500)/(p *0.1^2)=175,070.44 N/m^2The woman with small cross section area exerts more pressure as compared to the elephant withlarge cross section areaQ3)P=h ? ?=10 * 1000 *9.81=98100 N/m^2Q4) pressure is equal according to Pascal’s principle P=F/A =2000/0.002 =20000/AA=0.02 m^2 Q5) A1V1=A2V2 according to the equation of continuityA1 * 5=20 * 0.001A1=0.004 m^2But; area = pr^2=0.004 m^2r^2 =1.27324r=0.0357 mQ6) m1=4000 Kg; v1=39 m/sM2=2000 Kg; v2=15 m/sM1v1 + m2v2 = (m1+m2)v4000 * 30 +2000 *15 = (4000 + 2000)vV=25 m/sQ7) m1=0.05 Kg; u1=500 m/s; u2=300 m/sm2=5 Kg; v1=0; v2=…m1u1 + m2v1 = m1u2 + m2v20.05 * 500 +0 =0.05 *300 + 5 * v2V2= 2 m/sQ8)m1= 40 Kg; u1=0m/s; u2=15 m/sm2=30 Kg; v1=0 m/s; v2=…m1u1 + m2v2 =m1u2 + m2v2 0=40 * 15 +30 * v2-600=30v2v2=-20 m/s=20 m/s in opposite direction to the first one Q9) m1 =0.02 Kg; u1=0m/s; u2=350 m/sm2=10 Kg; v1=0m/s; v2=…Initially both the bullet and the gun were at rest with their velocities =0 m/s0=0.02 * 350 +10 *v2v2= -0.7 m/s0.7 m/s in opposite direction to the bulletK.E= (mv^2)/2(0.02 * 350^2)/2=1225 JQ10) m1=145g =0.145 Kgv1=44 m/s; v2=90 m/sImpulse =FtFt= m (v2-v1)F = m (v2-v1)/tF= 0.145 (90-44)/3 =2.2233 N "