"AnswersQ15) according to Newton’s second lawF= m(v-u)/t Ft=impact force Converting 57g to KgMass=0.057 KgV=7.0 m/s ; u=6.0 m/s-3 t= 4 * 10-3 F= 0.057(7.0-6.0)/4 * 10=14.25 NQ28)mass of cart 1=1.2 KgHeight of the ramp=1.8mMass of cart 2=2.0 KgExtension of the spring =2.0 cm =0.02mAccording to the law of conservation of energy, energy is neither create nor destroyed isonly converted to other forms of energyTherefore; P.E = K.E2 2 P.E =mgh while K.E= 1/2mv = 1/2ke for springs 2 1.2 * 9.81 *1.8 = 1/2 * K *(0.02)21.1896 = 0.0002KK = 105948 N/m2 2 b) 1/2mv = ½ * k *efor cart 12 2 mv = K *e2 2 1.2 * v = 105948 * 0.02V =5.943 m/s1 For cart 22 2 2.0 * v = 105948 * 0.002= 4.603 m/s2 c) H =v /2gv=5.943 m/s2 H = 5.943 /2*9.81=1.8 m-11 24 Q52)G =6.67 * 10; m= 5.98 * 102 2 v /r = Gm/r2 r = Gm/v -11 24 3 2 = [6.67 * 10 * 5.98* 10 ]/(7.45 * 10 )6 = 7.18645 * 10 mAltitude (h) = r – R6 6 =7.18645 * 10 – 6.378 * 10=808,450 mb)T= 2pr/v3 T = (2 * p * 808450)/7.45 * 10=681.832 seconds = 0.189398 hoursQ53)v= ? ? /? = 2? ? /?3 2 r = Gm * T /4p-11 26 2=[6.67 * 10 * 5.69 * 10 * 38700 ]/4 * pr= 112,918,932.7 m8 = 1.129189327 * 10 mb) The radius of the orbital is more as compared to that Saturn’s equatorial radius, since thesatellite is above the Saturn’s surface ratio = Saturn’s/satellite= 0.53401: 1 6 8 ratio= 6.371 * 10 /1.129189327 * 100 0.05642: 1The ratio of the satellite to the earth is lower as compared to that of satellite to Saturn -11 26 12 Q54)G =6.67 * 10 ; m=1.024 * 10 ; r= 4.5 * 10V= ? ? /?-11 26 6.67*10 *1.024*10 = 4.5*10^12 =38.9589 m/sb)Period (T) = 2pr/v12 = (2 * p *4.5 * 10 )/38.958911 =7.2575 * 10 seconds1 day =24 hrs.1 year =365 days * 24 hrs.= 201596618.4/365 * 24= 23013.31 years "