"In your experiment, caffeine can be easily extracted into dichloromethane, why doescaffeine prefer to transfer to dichloromethane over water? Explain Extraction is a method used for the separation of organic compound from a mixture ofcompound. This technique selectively dissolves one or more compounds into an appropriatesolvent. The solution of these dissolved compounds is referred to as the extract. In the case ofCaffeine extraction from tea powder, the solubility of caffeine in water is 22mg/ml at 25°C,180mg/ml at 80°C, and 670mg/ml at 100°C. Here the organic solvent Dichloromethane isused to extract caffeine from aqueous extract of tea powder because caffeine is more solublein dichloromethane (140mg/ml) than it is in water (22mg/ml).The dichloromethane - caffeinemixture can then be separated on the basis of the different densities of dichloromethane andwater because dichloromethane is much denser than water and insoluble in it. Residual wateris separated from dichloromethane by drain out the dichloromethane through separatingfunnel, thus dichloromethane passed through the funnel while polar solvents such as water isstill remains in the funnel. Water and dichloromethane is slightly soluble in each other. So,after separating the solvents, residual water will remain the organic layer. Mainly anhydrousis used for the removal of water from organic layer. Anhydrous sodium sulfite is an insolubleinorganic solid which will absorb water, thus drying it.Q19) The K Methylene Chlorine/water of an organic compound is 2.50. A solution ismade by dissolving 48 mg of the compound in 10 mL of water. How many milligram ofthe compound will be extracted usinga) One portion of 10 mL of methylene ChlorideConcentration=mass/1 litres of the solution=[ 48 *10^3]/[10*10^-3]= 4.8 g/lK = concentration of the compound/ concentration of methylene chlorinec 2.5= 4.8/concConcentration of methylene chloride = 1.92 g/l = 1920 mg/lIn 10 ml = 19.2 mgb) moleswill remain the same 1 portion = 19.2 mg in 10 ml2 portion = 38.2 mg in 10 ml5 ml in the two proportions 5 ml * 38.2 mg/10 ml= 19.1 mgQ20) The reaction will be speed up and the oxidation rate involved will take shorttime"