"720265-1-59P Earth is consisting of molecules which have a particular mass. The number of moles canbe found out if we divide the average mass of the human with the molecular mass.The number of moles in earth is given byMassofEarth() M N ? Molecularmass() m After getting the number of moles, we have to calculate the total number of objects bymultiplying the number of moles by the number of objects per mole. 28 Substitute, MassofEarth() M as 10 g and Molecularmass() m as 30g/moleMassofEarth() M N ? Molecularmass() m 28 10 g ? 30g /mole 26 ?? 3.3 10 mole 24 Now substitute the number of objects per mole as 1026 24 51 So number of molecules is 3.3?? 10 10 ? 10720265-1-61P The formula for area of a circular surface is given by,2 Ar ? ? ? Here, r is the radius of the circular field and ?? 22 / 7For, the Milky Way area is,2 Ar ? ? ?MM And for the solar system area is,2 Ar ? ? ?SS The areas are calculated as follows,21 Substitute, the radius of milky way, rm ? 10M2 Ar ? ? ? MM 22 21 2 ??(10 m)7 42 2 ?? 3.14 10 m 13 Similarly, substitute, the radius of the solar system, rm ?10s 2 Ar ? ? ? SS 22 13 2 ??(10 m)7 26 2 ?? 3.14 10 m Now the number of solar systems would it take to tile the disk of the Milky Way,A M N ? A S 42 2 3.14 ?10 m ?26 2 3.14 ?10 m 16 ?10 16 Therefore, the number of solar systems is 10 .d The relation between mass (m ), volume (v ) and density ( ) is,mass?? volume density m?? v d d ?m /v And the volume is denoted by,3 volume ?() length 3 vl ? The relation between angle, radius and arc isarc?? dis tance angle sD ?? ? (a) The density is calculated as follows, 22 6 Substitute the moon’s radius as lm ?? 1.7 10 and mass m ?10 kgThe approximate volume becomes,3 vl ? 63 ?? (1.7 10 m)18 3 ?? 4.913 10 m Density,22 10 kg d ? 18 3 4.413 ?10 m 1 43 ??10 kg /m4.413 43 ?? 0.22 10 kg /m (b) The approximate radius of the moon is given as,6 lm ?? 1.7 10 6 Therefore diameter is given as D=3.4 ?10 m(c) Now substitute in the equation of angle as?? c 11 ? ?? ? 2 2 180 c ? ? 360 Now substitute the value of radius of moon as s and the given angleDs ? / ? 6 1.7 ?10 m S? c ? D360 6 1.7?? 10 360 ? ? m 3.14 6 ?? 194.9 10 m 6 Therefore distance from earth is 194.9 ?10 m.d The relation between mass (m ), volume (v ) and density ( ) is,mass?? volume density m?? v d v ?m /d And the volume is denoted by,3 volume ?() length 3 vl ? First the volume is calculated as follows,?7 Substitute, typical length of a virus is 10 m?73 vm ? (10 ) ?21 3 ? 10 m 3 Now substitute density as 1/ kg m?21 3 3 m?? 10 m 1kg /m ?21 ?10 kg ?21 Therefore, mass of virus is 10 kg "