"Part A3 -2 0 1. a. 2 * 4 2= 8 * 0.0625 * 1 = 0.5½ 1/3 4/5 b. 81+8-32= 9+2-16 = -52m+3n m-n 2. a.(b ) / b n m n-m using a /a = a 2m+3n-m+n m+4n b= bb. (2 x -2)2 * (3 x 4)-32 2 * x -4 * 3 -3 * x -124 * 0.037 * x -16 = 0.1481 x -16--2b 3-d -3b 2d-1 c. ac/ acb 4-3d = a c 3. sequence of 4,12,36.......it is a geometric sequence in which common ratio is 3o 4. a. 240 = 240*(?/180) =1.33? =4.188b. -135o = -135*(?/180) = -0.75 ? =-2.355. f(x) = 9x +kx +92 2 -k= k-324k=18 2 2 6. (x -x – 6) / x– 42 2 x(x-3) +2 (x-3) / x – 2 (x+2) (x-3) / (x+2) (x-2)2 2 (x– x – 6) / x– 4 = (x-3) / (x-2) 27. x -81 = (x-9) (x+9)x=9, -98. f(x) = -2x-4range = -2<x>2domain= all real values of xPart B1. current amount = $7500invested for= 10 years at 6% / ato find : compounded monthly Solution: to find the amount we can use the formulan.t A = P (1 + r/n) A = total amount P = principle r = annual rate of interest n =number of times compounded per year t= time in years 12.10 A= 7500 (1 + 0.06/12) 120 = (7500) (1.005)=13645.47$to find the interest we use the formula A= P+II = A-P= 13645.47 – 7500=6145.472.To solve x,given, tan x = -1 , 0<x<360the tan has a period of?first we need to find all the solutions in the interval (0<x<2? )these are: x = 3 ?/4 and x = 7 ?/4add k ? to each of these solutions to get general form x= 3 ?/4 +kx or x= 7 ?/4 + kxwhere, k is an integer3. to find: sum of -77, -70, -65 ….+252n = l-A / dL=last term =252A =-77 = first term d=7n=(252+77)/7 = 47sum = n(l+a)/2sum = 47(252-77)/2 =4112.54. f(x) = 2/3(x-5)y= 2/3 (x-5)3y=2x-10x= 3y+10 /2f(12) = 3(12)+10 /2=23f(4) = 3(4)+10/2=11-1 -1 f (12) -f (4)/12-4 =23-11/14-4 =1.55. given data : f={(1,2), (2,5), (3,7), (4,8)}y= -2f(3x-6)+1A = {1,2,3,4}B = {2,5,7,8}we have to find a set of ordered pairs (a,b)such that a is factor of b; a<bSince 1 is a factor of 2; 1<2So (1,4) is one such ordered pair{(1,5), (1,7), (1,8)} are other such ordered pairs (1,2) = 2=> 2f(3*1-6)+12=-2f (-3)+12 = 6f+1 = f =1/6(2,5)= 5= -2f(3*2-6)+15=-2f(6-6)+1 f=0(3,7)=7=-2f(3*3-6)+17=-2f(3)+1f=1(4,8)= 8,-2f(3*4-6)+18=-2f(6)+1f=-7/12(2,5) (3,7) are the ordered pairs of y=-2f(3x-6)+19. f= {(1,1),(2,2),(3,3),(4,4)}y=-2f(1/2x-1)-1if x=0y=-2(-1)-1=1if y=0-2(1/2x -1) -1=01/2x -1 =-1/21/2x=1/2 => x=1if x=5y = -2 [1/10 -1]-1=-2[-9/10] -1=18/10-1 => 8/10 =4/5if y=55=-2[1/2x – 1] -13 = -1/2x +16x = -1+2x4x = -1 => x = -1/4new ordered pair is (5,5)Part C2 a. to solve: 2 sinx =1-sin x; 0<x<2 ? 22 sin x + sin x =1 "