"RC CircuitsObjectives:? To observe the current and charge of a capacitor during charging and discharging of acapacitorApparatus:? Capacitors? Digital meter? Timer? 1.5 V battery? Decade resistance? Analog ammeter? Knife- blade switchProcedure:Connect the DMM directly to the battery and note down the initial readings, made the basicconnections of the circuit as shown below:Connect the ammeters properly so that both can read positive voltages. Take your readingscarefully, make sure that the capacitor is initially uncharged. When you close the switch, startyour timing device at the exact same instant and let it run. At 5-sec interval take your readingsof V and V for a total of 180s. Once the capacitor has reached its final voltage, the capacitor isc R fully charged. Open the switch, remove the battery and close the gap. And now we take readingsfor the discharge process. Reset your timing device to zero, remove the battery and the close theswitch and start the timing device and take readings until the capacitor has reached its lowestvoltage level.Readings and Calculations: Charging DischargingT(s) V V I V V Ic R c R 0 0.001 1.388 9.25*10^-3 1.159 0 05 0.258 1.20 8*10^-3 1.00 0.938 6.25*10^-310 0.491 0.920 6.13*10^-3 0.831 0.814 5.42*10^-315 0.620 0.790 5.26*10^-3 0.686 0.691 4.60*10^-320 0.738 0.645 4.3*10^-3 0.570 0.566 4.3*10^-325 0.842 0.5320 4.1*10^-3 0.481 0.466 4.1*10^-330 0.993 0.441 3.86*10^-3 0.431 0.400 3.86*10^-335 1.027 0.371 3.12*10^-3 0.324 0.332 3.12*10^-340 1.083 0.310 2.68*10^-3 0.274 0.272 2.68*10^-345 1.029 0.261 1.74*10^-3 0.234 0.239 1.74*10^-350 1.066 0.220 1.42*10^-3 0.196 0.199 1.42*10^-355 1.2 0.188 1.11*10^-3 0.170 0.171 1.11*10^-360 1.239 0.159 1.03*10^-3 0.145 0.144 1.03*10^-365 1.253 0.136 0.98*10^-3 0.126 0.124 0.98*10^-370 1.271 0.117 0.96*10^-3 0.104 0.106 0.96*10^-375 1.286 0.102 0.89*10^-3 0.090 0.091 0.89*10^-380 1.299 0.089 0.78*10^-3 0.078 0.077 0.78*10^-385 1.310 0.078 0.76*10^-3 0.067 0.058 0.76*10^-390 1.319 0.068 0.72*10^-3 0.054 0.050 0.72*10^-395 1.326 0.057 0.69*10^-3 0.051 0.044 0.69*10^-3100 1.333 0.044 0.29*10^-3 0.044 0.038 0.29*10^-3105 1.331 0.044 0.29*10^-3 0.039 0.034 0.29*10^-3110 1.343 0.040 0.22*10^-3 0.034 0.030 0.22*10^-3115 1.346 0.038 0.20*10^-3 0.029 0.026 0.20*10^-3120 1.350 0.034 0.19*10^-3 0.026 0.024 0.19*10^-3125 1.353 0.034 0.19*10^-3 0.024 0.021 0.19*10^-3130 1.356 0.032 0.16*10^-3 0.022 0.019 0.16*10^-3135 1.357 0.030 0.13*10^-3 0.020 0.018 0.13*10^-3140 1.359 0.028 0.09*10^-3 0.018 0.016 0.09*10^-3145 1.360 0.026 0.07*10^-3 0.015 0.015 0.07*10^-3150 1.361 0.025 0.07*10^-3 0.015 0.014 0.07*10^-3155 1.363 0.023 0.06*10^-3 0.014 0.013 0.06*10^-3160 1.364 0.022 0.05*10^-3 0.013 0.012 0.05*10^-3165 1.366 0.021 0.04*10^-3 0.012 0.011 0.04*10^-3170 1.367 0.021 0.04*10^-3 0.011 0.010 0.04*10^-3175 1.368 0.020 0.03*10^-3 0.010 0.010 0.03*10^-3180 1.368 0.019 0.02*10^-3 0.010 0.010 0.02*10^-3R= 150OC=0.167F ( )( )( ) ( )( ) E=U+W= 0.0129+0.0015626=0.01446JGraphs:For Voltages:At charging:At discharging: For Current/Charge on capacitor:Conclusion:In this experiment we have observed the charging and discharging behaviour of the capacitor, instart the capacitor was made to be charged and the values are note down and then a plot isdrawn which shows that in charging the voltage on the capacitor starts to increase linearly andafter a few time constants it starts to achieve its final value, and then the graph becomes straightas shown above. And in discharging the battery is removed and the capacitor is allowed todischarge through a resistor, and the graph we observed forms a decaying exponential trend. Questions:1. U is the energy that is dissipated in the resistor when the current flows in the circuitR and W is the Work done by the battery to charge the plates of the capacitor. c 2. (a) True(b) True3. A decaying exponential4. We will fit the following equation to get an ideal curve:x y = a.b + c5. The errors was due to least count of the voltmeter as well as the timing sources and alsowe are assuming that the value is changing constantly in the experiment, but it waschanging exponentially due to which we might have missed some of the values, whichreduces our accuracy."