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Pin diagram of 8088 :
The pin diagram of 8088 is shown in given figure. Most of the 8088 pins and their functions are exactly similar to the corresponding pins of 8086. Hence the pins that have different functions ortimings are discussed in this section. Amongst them are the pins that have a common fun.
1) AD7-AD0 (Address/Data): These lines constitute the address/data time multiplexed bus. During T1 the bus is used for conducting addresses and during T2, T3, Tw andT4 states these lines are utilized for conducting data. These are tristate during 'hold acknowledges'and 'interrupt acknowledge' cycles.
2) A15-A8 (Address Bus): These lines provide the address bits A8 to A15 in the total bus cycle. These have not be latched for obtaining a stable valid address. These are active high and are tristated during the 'acknowledge' cycles. Notice, as the 8088 data bus is only of 8 bits, there is no requirement of the BHE signal.
3) SS0: A new pin SS0 is introduced in 8088 instead of BHE pin in 8086. In minimum mode, the pin 880 is logically equivalent to the S8 in maximum mode.
4) IO/M: This pin is similar to M/IO pin of 8086, but it givesan 8085 compatible memory/IO bus interface. The signals DT/R, IO/M, SSO might be decoded to interpret the activities of the microprocessor as in minimum and maximum mode.
Read Architecture : Look Aside Cache In "look aside" cache architecture the main memory is located conflictingthe system interface. Both the cache main memory sees a bus cycle
Interrupt System Based on Multiple 8259As A multiple 8259A interrupt system is diagrammed in given figure in this figure data bus drivers are not indicated, but they could be i
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how i can write a program to divide 2 numbers
Data copy/transfer Instructions MOV: This data transfer instruction transfers data from one register or memory location to another register or memory location. The source can
Software Interrupts Software interrupts are the result of an INT instruction in an executed program. It may be assumed as a programmer triggered event that immediately stops e
Memory Segmentation : The memory in an 8086/8088 based system is organized as segmented memory. In this scheme, the whole physically available memory can be divided into a n
write a program to divide 2 numbers
TEST : Logical Compare Instruction: The TEST instruction performs bit by bit logical AND operation on the 2 operands. Each bit of the result is then set to value I, if the equival
SHORT : The SHORT operator denoted to the assembler that only one byte is needed to code the displacement for a jump (for example displacement is within -128 to +127 bytes fr
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