Already have an account? Get multiple benefits of using own account!
Login in your account..!
Remember me
Don't have an account? Create your account in less than a minutes,
Forgot password? how can I recover my password now!
Enter right registered email to receive password!
Q. Draw the expression tree of the infix expression written below and then convert it intoPrefix and Postfix expressions.
((a + b) + c * (d + e) + f )* (g + h )
Ans:
The expression given is:
The postfix expression obtained is: ((a+b)+c*(d+e)+f)*(g+h) = ((ab+)+c*(de+)+f)*(gh+) = ((ab+)+(cde+*)+f)*(gh+) = ((ab+cde+*+)+f)*(gh+) = (ab+cde+*+f+)*(gh+) =(ab+cde+*+f+gh+*) The prefix expression obtained is: ((a+b)+c*(d+e)+f)*(g+h) = ((+ab)+c*(+de)+f)*(+gh) = ((+ab)+(*c+de)+f)*(+gh) = ((++ab*c+de)+f)*(+gh) = (+++ab*c+def)*(+gh) = (*+++ab*c+def+gh)
The postfix expression obtained is:
((a+b)+c*(d+e)+f)*(g+h)
= ((ab+)+c*(de+)+f)*(gh+)
= ((ab+)+(cde+*)+f)*(gh+)
= ((ab+cde+*+)+f)*(gh+)
= (ab+cde+*+f+)*(gh+)
=(ab+cde+*+f+gh+*)
The prefix expression obtained is:
= ((+ab)+c*(+de)+f)*(+gh)
= ((+ab)+(*c+de)+f)*(+gh)
= ((++ab*c+de)+f)*(+gh)
= (+++ab*c+def)*(+gh)
= (*+++ab*c+def+gh)
The data structure needed to evaluate a postfix expression is Stack
You need to implement a function which will write out a given user-specified memory location to disk in base 10. That means that you have to convert the large number data structure
There are four data type groups: Integer kepts whole numbers and signed numbers Floating-point Stores real numbers (fractional values). Perfect for storing bank deposit
You are given two jugs, a 4-gallon one and a 3-gallon one. Neither has any measuring marker on it. There is a tap that can be used to fill the jugs with water. How can you get exac
The number of interchanges needed to sort 5, 1, 6, 2 4 in ascending order using Bubble Sort is 5
Range: A Structured Type in Ruby Ruby has a numerous structured types, comprising arrays, hashes, sets, classes, streams, and ranges. In this section we would only discuss rang
If a node in a binary tree is not containing left or right child or it is a leaf node then that absence of child node can be represented by the null pointers. The space engaged by
differences between direct and indirect recursion
State the ways to construct container taxonomy There are several ways that we could construct our container taxonomy from here; one way that works well is to make a fundamental
Example of worse case of time
Get guaranteed satisfaction & time on delivery in every assignment order you paid with us! We ensure premium quality solution document along with free turntin report!
whatsapp: +91-977-207-8620
Phone: +91-977-207-8620
Email: [email protected]
All rights reserved! Copyrights ©2019-2020 ExpertsMind IT Educational Pvt Ltd